45=(2x)^2/(0.03-x)(0.03-x)

Solution for 45=(2x)^2/(0.03-x)(0.03-x) equation:

45=(2x)^2/(0.03-x)(0.03-x)

We move all terms to the left:

45-((2x)^2/(0.03-x)(0.03-x))=0


Domain of the equation: (0.03-x)(0.03-x))!=0

We move all terms containing x to the left, all other terms to the right

-x)(0.03-x)!=-0.03

x∈R


We add all the numbers together, and all the variables

-(2x^2/(-1x+0.03)(-1x+0.03))+45=0

We multiply parentheses ..

-(2x^2/(+x^2-0.03x-0.03x+0.0009))+45=0

We multiply all the terms by the denominator


-(2x^2+45*(+x^2-0.03x-0.03x+0.0009))=0


We calculate terms in parentheses: -(2x^2+45*(+x^2-0.03x-0.03x+0.0009)), so:

2x^2+45*(+x^2-0.03x-0.03x+0.0009)

We multiply parentheses

2x^2+45x^2+0x+0x+0.0405

We add all the numbers together, and all the variables

47x^2+2x+0.0405

Back to the equation:

-(47x^2+2x+0.0405)


We get rid of parentheses

-47x^2-2x-0.0405=0

a = -47; b = -2; c = -0.0405;
Δ = b2-4ac
Δ = -22-4·(-47)·(-0.0405)
Δ = -3.614
Delta is less than zero, so there is no solution for the equation